刷题

第2天的作业打卡

给定任意一个整数

  1. 输出该整数有多少个数字是大于0的
  2. 输出该整数中有多少个偶数数字，有多少个奇数数字

可以当成字符串来处理，也可以当成整数来处理。

当成整数来处理

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positive_numbers=[]
odd_numbers=[]
even_numbers=[]

try:
    number = int(input("An integer please: "))
except ValueError:
    print('Input is not an integer, giving up.')
    sys.exit()

while number:
    number, digit = divmod(number, 10)
    if digit != 0:
        positive_numbers.insert(0, digit)
    if digit % 2 == 0:
        even_numbers.insert(0, digit)
    else:
        odd_numbers.insert(0, digit)

res1=', '.join(str(item) for item in positive_numbers)
res2=', '.join(str(item) for item in even_numbers)
res3=', '.join(str(item) for item in odd_numbers)

当成字符串来处理

精简前

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def postive_numbers(value):
    p_n = 0
    res = []
    for character in value:
        if int(character) > 0:
            p_n += 1
            res.append(character)
    output = ', '.join(res)
    print(f'有{p_n}个数字大于0, 分别是{output}')

def odd_or_not(value):
    o_n = 0
    e_n = 0
    res1, res2 = [], []
    for character in value:
        if int(character) % 2 != 0:
            o_n += 1
            res1.append(character)
        else:
            e_n += 1
            res2.append(character)
    output1 = ', '.join(res1)
    output2 = ', '.join(res2)
    print(f'有{e_n}个偶数数字: 分别是{output2},有{o_n}个奇数数字: 分别是{output1}')

if __name__ == '__main__':
    value=input("An integer please: ")
    postive_numbers(value)
    odd_or_not(value)

精简后

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def postive_numbers(value):
    res = [character for character in value if int(character) > 0]
    output = ', '.join(res)
    print(f'有{len(res)}个数字大于0, 分别是{output}')

def odd_or_not(value):
    res1 = [character for character in value if int(character) % 2 != 0]
    res2 = [character for character in value if int(character) % 2 == 0]
    output1 = ', '.join(res1)
    output2 = ', '.join(res2)
    print(f'有{len(res2)}个偶数数字: 分别是{output2}, 有{len(res1)}个奇数数字: 分别是{output1}')

if __name__ == '__main__':
    value = input("An integer please: ")
    postive_numbers(value)
    odd_or_not(value)

快来参与讨论吧~